DSE Style Example
Example question:The relationship between a shop's monthly sales y ($10,000) and advertising expenses x ($10,000) can be expressed as a function y = -x² + 8x + 20, where 0 ≤ x ≤ 10.
(a) What is the cost of advertising to maximise monthly sales?
(b) What is the range of advertising costs if monthly sales are to exceed $350,000?
Answer:
(a) y = -x² + 8x + 20 = -(x² - 8x) + 20 = -(x - 4)² + 16 + 20 = -(x - 4)² + 36
When x = 4, y has a maximum value of $360,000.
(b) To make y > 35, i.e. -x² + 8x + 20 > 35
-x² + 8x + 20 - 35 > 0
-x² + 8x - 15 > 0
x² - 8x + 15
(x - 3)(x - 5)
Therefore 3